Solucionario Ciencia E Ingenieria De Los Materiales Askeland 3 Edicion -

[ \frac{1,2 - 0,45}{1,2 - 0,10} = \frac{0,75}{1,10} = 0,6818 ]

Buscamos en tabla de erf(z): erf(z) = 0,6818 → z ≈ 0,71 (interpolando). [ \frac{1,2 - 0,45}{1,2 - 0,10} = \frac{0,75}{1,10}

( t \approx 6,3 , \text{horas} ).

I understand you're looking for a long write-up related to the solution manual for "Ciencia e Ingeniería de los Materiales" (The Science and Engineering of Materials) by Donald R. Askeland, 3rd edition (Spanish version). 10} = \frac{0

Usamos la función error complementaria: 10} = 0

[ 0,71 = \frac{0,0008}{2\sqrt{(1.4\times10^{-11}) t}} ]