Let F₁ = force in bronze, F₂ = force in steel. Equilibrium: ΣM = 0 → F₁ a + F₂ b = P*c (specific distances depend on figure; assume symmetrical so F₁+F₂ = P). Compatibility: δ₁ = δ₂ → (F₁L₁)/(A₁E₁) = (F₂L₂)/(A₂E₂). Solve simultaneously.
Rectangular beam (b=100 mm, h=200 mm) with M=20 kN·m. Find max bending stress. solucionario resistencia de materiales schaum william nash
Steel column (E=200 GPa) solid circular d=40 mm, L=2 m, pinned ends (K=1). Find critical load. Let F₁ = force in bronze, F₂ = force in steel
Let F₁ = force in bronze, F₂ = force in steel. Equilibrium: ΣM = 0 → F₁ a + F₂ b = P*c (specific distances depend on figure; assume symmetrical so F₁+F₂ = P). Compatibility: δ₁ = δ₂ → (F₁L₁)/(A₁E₁) = (F₂L₂)/(A₂E₂). Solve simultaneously.
Rectangular beam (b=100 mm, h=200 mm) with M=20 kN·m. Find max bending stress.
Steel column (E=200 GPa) solid circular d=40 mm, L=2 m, pinned ends (K=1). Find critical load.